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Tempestt Graphs a Function that has a Maximum Located at (–4, 2). Which could be her graph?

Answer :

Tempestt Graphs a Function that has a Maximum Located at 4 2. Which could be her graph

Function: f(x) = a(x-h)^2 + k

Correct Answer:

The function has a maximum and a downward-opening curve, so the parabola opens downward, with a maximum at (-4, 2) that goes through (-6,-2) and (-2,-2).

Related Question: Which Set of Angles can Form A Triangle.

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